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Mathematics 23 Online
OpenStudy (anonymous):

Prove: 1 + sinx = sinx (1+cscx) I would use the reciprical identity: R.S: (1 + 1/sinx) Then what

OpenStudy (anonymous):

cscx = 1/sinx

OpenStudy (anonymous):

sinx (1+cscx) =sinx (1 + 1/sinx)

OpenStudy (anonymous):

ie Sinx + 1 LHS=RHS

OpenStudy (anonymous):

how u get that last step?

OpenStudy (anonymous):

u multiply sinx(1+1/sinx) that doesnt give u sinx + 1 does it?

OpenStudy (anonymous):

|dw:1352127339058:dw|

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