Question

\[ \frac{dy}{dx}=\sqrt{y^2-1} \]

Answer 1

Boundary conditions are\[y(a)=y(-a)=1\]

Answer 2

\[\frac{dy}{\sqrt{y^2-1}}=dx\]
Separation of variables.
Now integrate both sides. :

Answer 3

Why didn't I see that?! Thanks