An engineer is surveying a building with a device that is 5 feet above the ground. He is 50 feet from the building and is looking with an angle of elevation of 50°. How tall is the building?
PLEASE! I REALLY need help! I DO NOT get this at all--PLEASE SOLVE!
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OpenStudy (anonymous):
Do you know any Trig?
OpenStudy (anonymous):
A tangent function is most appropriate here.
OpenStudy (anonymous):
you can use tangent = opp/adj for this
you have this triangle and solve for x
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OpenStudy (anonymous):
Remember Sin is opp/adj. Sin(50 degrees) = x/50ft.
Solve for x and then remember to add the extra 5ft.
OpenStudy (anonymous):
solve for x then add 5
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OpenStudy (anonymous):
use tan and make sure your calc is in degrees :)
OpenStudy (anonymous):
I'm sorry use tangent. Not sin.
OpenStudy (anonymous):
tan is opp/adj
sin is opp/hyp
so tan is appropriate for this
OpenStudy (anonymous):
put this in your calculate tan(50)(50)
OpenStudy (anonymous):
after you get that answer add 5 to it and thats your answer
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