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Mathematics 18 Online
OpenStudy (anonymous):

cos^2 x + 2 cos x + 1 = 0 Find all solutions in the interval [0, 2π). HELP :(

OpenStudy (anonymous):

Factor, then solve over interval

OpenStudy (anonymous):

how do I do that!? D: @Brittni0605

OpenStudy (anonymous):

\[\cos ^{2}x + 2cosx+1=0\]

OpenStudy (anonymous):

\[(cosx+1)(cosx+1)=0\]

OpenStudy (anonymous):

\[cosx+1=0\]

OpenStudy (anonymous):

\[cosx=-1\]

OpenStudy (anonymous):

\[x=\cos^{-1}( -1)\]

OpenStudy (anonymous):

\[x=\Pi \]

OpenStudy (anonymous):

Is that answer taking into consideration the solution has to be in the interval of [0,2π)? @Brittni0605

OpenStudy (anonymous):

Yes.

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