Question

H10P2 - i (Last Part)
Does anyone have the result for this? When R1 is in Series with C and R2 in Series with L and those two branches Parallel, what is the impedance for w->inf?

Answer 1

oh ok, got the answer with some thinking. Simply R1 :)

Answer 2

H10P2

A) R1+R2+j*w*L+(1/(j*w*C))
B) inf
C) inf
D) ((((R1+R2)*(j*w*L))/((R1+R2)+(j*w*L)))*(1/(j*w*C)))/((((R1+R2)*(j*w*L))/((R1+R2)+(j*w*L)))+(1/(j*w*C)))
E) 0
F) 0
G) ((R1+(1/(j*w*C)))*(R2+j*w*L))/((R1+(1/(j*w*C)))+(R2+j*w*L))
E) R2
F) R1