Question

hmmm checking

Answer 1

\[\sum F_x=ma_x=mgsin\theta -f \]

Answer 2

\[\sum F_y=ma_y = N-mgcos\theta =0 \]

Answer 3

\[\tau=fR=I\alpha \]
\[\frac {I\alpha }{R}=f\]

Answer 4

For this, Solid sphere,

\[f=\frac {\frac {2}{5}mR^2 \alpha }{R}=\frac {\frac {2}{5}mR^2}{R}(\frac {a}{R})=\frac{2}{5}ma \]

Answer 5

\[\sum F_x=ma_x=mgsin\theta -\frac{2}{5}ma\]

\[\frac {7}{5}ma_x=mgsin\theta\]

Answer 6

\[\frac{7}{5}a_x=gsin\theta \]

Answer 7

which is right so now this one