Question

find the critical points for f(x)=cos^2(x) on [-pi,pi]

Answer 1

hey r u there

Answer 2

f'(x)=2(cos(x))(-sin(x))
for critical points set f'(x)=0
cos(x)=0
x=pi/2
and
-sin(x)=0
x=0,pi/2

Answer 3

x=pi/2,0,-pi/2