Question

-3x-y=-10
4x-4y=8

Answer 1

I'm going to assume that you are solving a system of equations:

-3x-y=-10
4x-4y=8

The easiest way to solve this is through substitution. In other words, you use one equation to solve for x and then sub that into the other equation and solve for y. Then, go back and plug in y now in an equation to determine x.

So:

-3x-y=-10
-y=-10+3x
y=10-3x

4x-4y=8
I would first simplify this to:
x-y=2 //By simply dividing by 4 on each side.

x-y=2
x-(10-3x)=2
x-10+3x=2
4x=12
x=3

Then put that back into any equation in the system, we'll use the first one:

-3x-y=-10
-3(3)-y=-10
-9-y=-10
-y=-1
y=1

You can check by using any equation:

4x-4y=8
4(3)-4(1)=8
12-4=8
8=8

Therefore, the solution to your system of equations is x=3 and y=1 or (3,1)

Answer 2

multiply the first function by (-4)
you'll get
12x+4y=40
and you have
4x-4y=8

add them
y cancel
16x=48
x=48/16
x=3

plug x=3 to any function to get y
4(3)-4y=8
12-4y=8
4y=12-8
4y=4
y=1

Answer 3

Can Someone help with my problem?
Go to my question and here is the pic for it

Answer 4

Only a map