Question

simplify the sqaure root of 108

Answer 1

108=36(3)
SQUARE ROOT 36=6
SQUARE ROOT 108=6 times square root of 3

Answer 2

\[\sqrt{36 * 3}\]
\[\sqrt{6*6*3}\]
Then the primes
\[\sqrt{2*3*2*3*3}\]

But I think in your case for simplicity is
\[\sqrt{108} \] =\[\sqrt{36*3}\] \[\sqrt{6} \sqrt{6} \sqrt{3}\] \[6 \sqrt{3}\]