Question

hello can you help me with some math problems ? The first is solve this differantial equation y´ = -3y, y(0)=1

Answer 1

given dy/dx =-3y
(using method of seperation ) we have
dy/y =-3 dx
integrating we have ln y -ln c = -3x or ln(y/c) =-3x
or y = c e^(-3x) c is integrating constant
given at x=0 y=1
hence we have 1= c e^(-3.0) or 1=c
hence the required solution is y = e^(-3x)

Answer 2

Thank you :-)

Answer 3

welcome....