Question

The equation of the line of symmetry pf the curve y=x^(2)+px+21 is x=4. Find the value of p.

Answer 1

is p=-8

Answer 2

stpes?

Answer 3

here is y-5=(x-4)^2

Answer 4

for x=4 the line of symmetry thr rhs of the equation should have (x-4)^2 =x^2-2(4)x+16
hence coefficient of x is -8
thus p=-8

Answer 5

what is it ? how come?
y-5=(x-4)^2

Answer 6

hey...