Question

hw10 part 3

Answer 1

H10P3

a) (((j*w*L+R2)*(1/(j*w*C))/(j*w*L+R2+(1/(j*w*C))))/((j*w*L + R2)*(1/(j*w*C))/(j*w*L+R2+(1/(j*w*C)))+R1)*(R2/(j*w*L + R2)))
b) ((j * w * L + R2) * (1 / (j * w * C))) / (j * w * L + R2 + (1 / (j * w * C )))
c) (sqrt (R1/R2 -1)) / (w * R1)
d) ((sqrt (R1/R2 -1)) * R2) / w
e) Change values in C (with w = 2*pi*f) be careful, because the f is normaly in Khz (*10^3)
f) Change values in D (with w = 2*pi*f) be careful, because the f is normaly in Khz (*10^3)

Answer 2

part e answer is: 1101.175
part f: 55.0587

Answer 3

correct is
part e anwser is: 889.4pF
part f answer is: 44.5uH

Answer 4

Lmatch = sqrt(R1R2 – R2^2)/w and Cmatch = R1R2/(w*sqrt(R1R2 –
R2^2))

Answer 5

becarful there are diferent values for someone....

Answer 6

@dubiduba we might be having different values for R1 and R2 it all depends on the previous 2 formulas of Lmatch and Cmatch.

Answer 7

Cmatch = 1/(w*sqrt(R1R2 – R2^2))

Answer 8

Lmatch = sqrt(R1R2 – R2^2)/w

Answer 9

Part-1 ?????

Answer 10

confused with the last 2

Answer 11

w??

Answer 12

w = 2*pi*f
see the question
C in Pico
F in Micro

Answer 13

Finally got the h9p1 completely......guys those who are strugling with h9p1 part e
they need to use the formula.with sin term as 1.

Answer 14

H10P3 e &f ans please

Answer 15

giv me ur question pls

Answer 16

w = 2*pi*f
Cmatch = 1/(w*sqrt(R1R2 – R2^2))
Lmatch = sqrt(R1R2 – R2^2)/w