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what is the solution set of x^2-8x+52=0
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It is a quadratic equation which can be solved by either factorisation or using a quadratic fomula
ok can you help factorize then
ok
What are the numbers which you can multiply to get 52 and add or subtract to get -8?? First lets right the factors of 52
7 8
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!!
nevermind
For this one it is better to use a quadratic formula
4-6i,4+6i
gotit
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\[x=\frac{ -b+or-\sqrt{(b ^{2}-4ac} }{ 2a }\]
\[ax ^{2}+bx+c\]
\[x^2-8x-52=0\] \[x^2-13x+4x-52=0\] \[x(x-13)+4(x-13)=0\] \[(x-13)(x+4)=0\]
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