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x^3-5x^2-66x=0
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does it really say \(x^3-5x-66x=0\)?
yeah
so i guess it is really \[x^3-71x=0\]
oh wait 5x^2 sorry
\[x^3-5x^2-66x=0\]
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start with \[x(x^2-5x-66)=0\] one solution is obviously \(x=0\) to find the others solve \[x^2-5x-66=0\] by the quadratic formula, or factoring if you think it factors
by some miracle this one does factor as \[x^2-5x-66=0\] \[(x-11)(x+6)=0\]and then you should be good to go
Thank you so much (:
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