Question

How do I prove this by using trig identities: (2sin^2x-1)/(sinxcosx)/=tanx-cotx

Answer 1

\[2 \sin^2 x-1= 2\sin^2x-(\sin^2x+\cos^2x)= \sin^2x-\cos^2x \]

Answer 2

how does that equal to sin^2x-cos^2x

Answer 3

sin^2 x + cos^2x=1

Answer 4

sin^2x-cos^2x/sin^2xcosx..now what do i do

Answer 5

\[\frac{ \sin^2 }{ \sin x *\cos x }- \frac{ \cos^2 x }{ sinx * \cos x }= tanx - \cot x\] clear?

Answer 6

@sabika13 hope that helps you

Answer 7

how doss sin^2/sinxcosx=tanx?

Answer 8

does

Answer 9

how about now?