Question

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Answer 1

y = x^2+5x-3 .... (1)
y-x = 2 or y = x + 2 .... (2)
subtitute (2) to (1),
x^2+5x-3 = x + 2
x^2+5x-3 -x - 2 = 0
x^2 + 4x - 5 = 0
(x+5)(x-1) = 0
zeros, take x+5 = 0, so x1=-5 and
x-1 =0, so x2 =1
from (2) :
y = x + 2
so, y1 = -5 + 2 = -3 and
y2 = 1 + 2 = 3
the solution are {(-5,-3),(1,3)}

Answer 2

Thx :)

Answer 3

welcome :)