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Suppose that the derivative of a function satisfies the formula f'(x)=4f(x)+2x. If f(3)=6, use linear approximation to estimate the value of the function at 3.008. f(3.008)=?
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your point is \((3,6)\) and your slope is \(f'(3)=4\times f(3)+2\times 3=4\times 6+6=30\)
use the point slope formula to find the equation of the line
\[y-6=30(x-3)\] then replace \(x\) by \(3.008\) get \[y=30(.008)+6\] whatever that is
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