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\[y = (x+1)(x+3) = x^2 + 4x +3\]
It's multiple choice and I don't see that as an answer D:
What are the choices?
The choices are : y = x^4 –4x^3 – 4x^2 – 4x – 3 y = –x^4 + 4x^3 + 4x^2 + 4x + 3 y = x^4 +4x^3 + 3x^2 + 4x – 4 y = x^4 + 4x^3 +4x^2 + 4x + 3
Sorry, thought you misspelled quadratic as quartic. The last option, \[y = x^4 + 4x^3 + 4x^2 + 4x + 3 = (x+1)(x+3)(x^2 + 1)\]
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Thank you :D I couldn't figure out the answer for the longest time.
You're very welcome. I just tried factoring (x+1)(x+3) out of the equations.
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