Question

Closed question now.

Answer 1

\[y = (x+1)(x+3) = x^2 + 4x +3\]

Answer 2

It's multiple choice and I don't see that as an answer D:

Answer 3

What are the choices?

Answer 4

The choices are :
y = x^4 –4x^3 – 4x^2 – 4x – 3
y = –x^4 + 4x^3 + 4x^2 + 4x + 3
y = x^4 +4x^3 + 3x^2 + 4x – 4
y = x^4 + 4x^3 +4x^2 + 4x + 3

Answer 5

Sorry, thought you misspelled quadratic as quartic. The last option,
\[y = x^4 + 4x^3 + 4x^2 + 4x + 3 = (x+1)(x+3)(x^2 + 1)\]

Answer 6

Thank you :D
I couldn't figure out the answer for the longest time.

Answer 7

You're very welcome. I just tried factoring (x+1)(x+3) out of the equations.