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anyone help.... i'm stuck at doing cotx= 3/2. how you do it? I replaced cotx with cosx/sinx, but i end up not knowing how to solve it. please help! :D
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try writing \[cotx = \frac{1}{tanx}\]
\[\frac{1}{tanx} = \frac{3}{2} => 1 = \frac{3}{2}tanx => \frac{3}{2}tanx = 1 => 3 tanx = 2 => tanx = \frac{2}{3}\]
now solve for \(x\)
got it. 33.7 :) thanks!
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