Question

find f''(x) if
f(x)=x(6^(x^2+3))

Answer 1

Current work:\(\huge f''(x)=\ln6(6^{x^2+3})(4\ln6*x^3+6x)\)

Answer 2

What am I doing wrong?

Answer 3

work:
for f'(x), set apply the product rule, getting
u=x u'=1
v=6^(x^2+3) v'=2 ln6*x*6^(x^2+3)
the result is 2ln6*x^2*6^(x^2+3)+6^(x^2+3)

Answer 4

for f''(x), factor out constants, 2ln6 d/dx (x^2+6^(x^2+3))+ d/dx (6^(x^2+3))

Answer 5

Nevermind I got this right apparently.