Question

x^3-8/x^2+2x+4 (x^2-4) i need help please My answers are all partial credit apparently, i dont know what im doing wrong, please help...

Answer 1

i think x^3-8/x^2+2x+4 divided by (x^2-4)

= (x^3-8) / ((x^2+2x+4)(x^2-4))
= ((x-2)(x^2+2x+4)) / ((x^2+2x+4)(x^2-4)) ... factorise x^3-8
= (x-2) / (x^2-4) ... divide numerator and denominator by x^2+2x+4
= (x-2) / ((x+2)(x-2)) ... factorise x^2 - 4
= 1 / (x+2) ... divide numerator and denominator by x-2

Answer 2

is this the same problem

Answer 3

@surdawi

Answer 4

\[\frac{ (x^3-8) }{ ((x^2+2x+4)(x^2-4)) }\]
if so you got it