Given a rectangle whose perimeter is 48 inches. The length of the rectangle is 4 inches longer than the width. What are the length and width of this rectangle. (The formula for the perimeter of a rectangle is P = 2l + 2w)

Question

Given a rectangle whose perimeter is 48 inches. The length of the rectangle is 4 inches longer than the width. What are the length and width of this rectangle.  (The formula for the perimeter of a rectangle is P = 2l + 2w)

anonymous · Answer

Length = 14 inches and Breadth/Width = 10 inches.

anonymous · Answer

Length = l
Breadth = b
2(l+b) = 48
l+b = 24----> Equation 1

Equation 2:
l = b + 4

Now, substitution Equation 1 in Equation 2 :

b + 4 + b = 24 
2b = 20
Therefore, b = 10.
And substituting the answer in Eq.2, we get l= 10 + 4 which is 14.
Therefore, l = 14 and b = 10.