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Precalculus
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OpenStudy (anonymous):
what is x^2+1/x^2-x-2
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OpenStudy (anonymous):
Hi Cameron (:
OpenStudy (anonymous):
(x + 1) / (x - 2 )
OpenStudy (anonymous):
thanks
OpenStudy (anonymous):
wrong, x^2+1 is not the the same as (x+1)^2. so the right answer is (x^2+1)/(x+1)(x-2).
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