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Precalculus 10 Online
OpenStudy (anonymous):

what is x^2+1/x^2-x-2

OpenStudy (anonymous):

Hi Cameron (:

OpenStudy (anonymous):

(x + 1) / (x - 2 )

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

wrong, x^2+1 is not the the same as (x+1)^2. so the right answer is (x^2+1)/(x+1)(x-2).

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