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OpenStudy (anonymous):
x^3-8/x^2+2x+4 (x^2-4) i need help pleasei think this can check my answers please think x^3-8/x^2+2x+4 divided by (x^2-4) = (x^3-8) / ((x^2+2x+4)(x^2-4)) = ((x-2)(x^2+2x+4)) / ((x^2+2x+4)(x^2-4)) ... factorise x^3-8 = (x-2) / (x^2-4) ... divide numerator and denominator by x^2+2x+4 = (x-2) / ((x+2)(x-2)) ... factorise x^2 - 4 = 1 / (x+2) ... divide numerator and denominator by x-2
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