Question

√(x+2)+4=x
Help, please! This is my last problem!!

Answer 1

\[\LARGE \sqrt{x+2}+4=x\]

Answer 2

start with
\[\sqrt{x+2}=x-4\] square both sides to get
\[x+2=(x-4)^2\]\[x+2=x^2-8x+16\]\[x^2-9x+14=0\] then factor

Answer 3

\((x-7)(x-2)=0\) so either \(x=7\) or \(x=2\) now check to see if they work

Answer 4

7 works because
\[\sqrt{7+2}+4=7\] but 2 does not

Answer 5

Thank you :D