correct these calculations by changing either side of each equation.

a. (x+1)-(2x+1) = -x+2

Question

correct these calculations by changing either side of each equation.

a. (x+1)-(2x+1) = -x+2

anonymous · Answer

$$(4p ^{2}-3q)-4(p ^{2}-q)=7q$$

anonymous · Answer

thats for b.

anonymous · Answer

c. $$5k(k+1)-(k ^{2}+5)=4k ^{2}$$

lukebluefive · Answer

a.
$$(x+1)-(2x+1) = -x+2$$
Remove the parenthesis:
$$x+1-2x-1 = -x+2$$
Combine like terms:
$$x-2x+1-1 = -x+2$$

lukebluefive · Answer

b. Similarly to part a:
$$(4p^2−3q)−4(p^2−q)=7q$$
Remove parenthesis:
$$4p^2−3q−4p^2+4q=7q$$
Combine like terms:
$$4p^2−4p^2−3q+4q=7q$$

lukebluefive · Answer

c.
$$5k(k+1)−(k^2+5)=4k^2$$
Multiply out:
$$5k^2 + 5k−(k^2+5)=4k^2$$
Remove parenthesis:
$$5k^2 + 5k−k^2-5=4k^2$$
Combine like terms:
$$5k^2−k^2 + 5k-5=4k^2$$

lukebluefive · Answer

As you can see, none of these are actually equivalent.  You have to change one of the sides (usually a plus or minus or a constant) to make them correct.

anonymous · Answer

ok :D thanks for helping :D

lukebluefive · Answer

You're welcome.  Glad I could help.  ^_^