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find the derivative of lnx / x^2 ?
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(vu'-uv')/v^2 u=lnx , v = x^2
I get the quotient rule but dont know what to do with the 2x(lnx) on the top? Does it end up 2lnx^2?
no it doesnt... well i dont think so.
2x(lnx) just leave it like this.. it's still a correct answer.
thanks
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