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sec x / csc x
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When in doubt, convert to sine and cosine and see what happens.
Remember, \(\sec x = \dfrac{1}{\cos x}\) and \(\csc x = \dfrac{1}{\sin x}\) So \(\Huge \dfrac{\sec x}{\csc x} = \dfrac{\dfrac{1}{\cos x}}{\dfrac{1}{\sin x}} = \dfrac{\sin x}{\cos x} = \boxed{ \tan x}\)
Is this clear?
thn u replace d value of x
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