Question

Decided to play around with the FizzBuzz problem talked about in recitation. I expect this to stop @ 99 instead of 100,
i = 0
while i < 100 :
i += 1
print (i)
and this to stop at 100 instead of 101,
i = 0
while i <= 100 :
i += 1
print (i)

Can someone give me some insight here? Thanks!

Answer 1

well your codes are both valid...what do you need to know? other ways to write the same thing?

Answer 2

What I don't get is that int he first code set where i<100 the list prints out to 100. Shouldn't this stop @ 99 since 99 is less than 100 but 100 is equal to 100?

In the second code set where i<=100 shouldn't this stop at 100 not 101 for the same reason?

Answer 3

oh yes,
i = 0
while i < 100 :
print (i)
i += 1
try this

Answer 4

Why does adding the print statement make this correct?

Answer 5

well you practicaly print i before it goes +1 so:

*You start with i=0 ,so you print 0.
*Then it goes i=i+1 (its the same as i+=1).
So you enter while loop again ,since i that is equal to 1 now is still less than 100.
and you print 1.
*then again i+=1 ,so now i =2, it passes the test and enters while..prints i (2).
*adds 1 again etc.....when i becomes 99 ....99<100 is true so it prints i that is 99 and adds 1 to i. --> 100
*100 <100 is false so it does NOT enter the while loop and does NOT print 100.



for the 2nd code 100<=100 is true so it enters while , prints 100 and goes 101.
for 101 it does not enter while loop as it fails the test.


hope that helps

Answer 6

Makes sens thanks