Question

y=xln(x)
y1=1+lnx
if i want the criticle points then i set 1+lnx=0 but how do you do this or am i wrong on something?

Answer 1

y1=1+lnx

what's that?

Answer 2

ok, that's fine then..

Answer 3

ln(x) =-1
x=e^-1

Answer 4

yee im starting to get it now... basically e^-1 since the base is e and the other side is -1

Answer 5

yes, exactly.

Answer 6

this makes sense now.. idk y i couldnt think of this b4 on the quiz....