Question

...

Answer 1

First find the x coordinate of the vertex

Answer 2

it should be

x = -b/(2a)

NOT

x = b/(2a)

Answer 3

y+4 = x^2+12x
y+4+36 = x^2+12x+36
y+40 = (x+6)^2
y = (x+6)^2 - 40
y = (x-(-6))^2 + (-40)
.
Now, we see that:
(h,k) = (-6,-40)

Answer 4

no, it's NOT x = b/(2a)

it should be x = -b/(2a)

Answer 5

YES

Answer 6

so

x = -b/(2a)

x = -12/(2(-1))

x = ???

Answer 7

robert2 is incorrect because his first step is missing a negative sign on the x^2 term

Answer 8

IS CORRECT MY TEACHER ME EXPLAIN

Answer 9

NO

Answer 10

y = -1x^2 + 12x - 4

y = -1(6)^2 + 12(6) - 4

y = 32

Answer 11

so it should be

y = -1(x - 6)^2 + 32

Answer 12

yw