Question

I need help finding the indicated trigonometric value in the specified quadrant.

Function: Sin theta = -3/5
Quadrant: IV
Trigonometric Value: Cos theta

The answer says I should have gotten 4/5 but I don't know how to get that. :/

Answer 1

think of a 3 - 4 - 5 right triangle, and take the appropriate ratios

Answer 2

you can solve for \(a\) by \(a^2+3^2=5^2\)
\(a^2+9=25\)
\[a^2=16\]\[a=4\]

Answer 3

wow i was doing the math in my head WRONG the whole time
i kept thinking 25-9 = 14. NO WONDER I WAS I GETTING IT WRONG. thank you!!! lol