Question

\frac{ SEC(X) CSC(X) }{ SIN(X)COS(X) }=COT(X)TAN(X) Verify This..

Answer 1

\[\frac{ SEC(X) CSC(X) }{ SIN(X)COS(X) }=COT(X)TAN(X)\]

Answer 2

Answer

Answer 3

\[\frac{ 1 }{ SIN(X)COS(X) } \to \frac{ COS(X)^{2} + SIN(X)^{2}}{ SIN(X)COS(X)}\] how do you get to this?

Answer 4

cos(x)^2 + sin(x)^2 = 1
thats an identity

Answer 5

oh

Answer 6

ok i get that problem now but a new question \[\tan (X+\frac{ \pi }{ 2 }) = - COT(X)\]

Answer 7

i used the sum of differences then i saw \[\tan \frac{ \pi }{ 2 }=Undefined\]

Answer 8

sorry im not sure i can help you with just, you should close this question and ask it again so other people may help you