Question

find the inverse laplace transform of (36s^4+12s^2+1)/s^6

Answer 1

\[\frac{ 36s ^{4}+12s^{2}+1 }{ s^6}\]

Answer 2

36/s^3 + 12/s^4 + 1/s^6
do it individually.

Answer 3

http://www.wolframalpha.com/input/?i=inverse+laplace+transform+1%2Fs^n
\( \Gamma(n) = (n-1)! \)