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Water is pumped out of a holding tank at a rate of 3-3e^-0.13t liters/minute, where t is in minutes since the pump is started. If the holding tank contains 1000 liters of water when the pump is started, how much water does it hold one hour later?
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integerate 3-3e^-0.31t then plug 3600 for 1 hour later then minus that from 1000
V=1000-3t+3*0.31e^-0.31t plug 3600 in eauation
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