Water is pumped out of a holding tank at a rate of 3-3e^-0.13t liters/minute, where t is in minutes since the pump is started. If the holding tank contains 1000 liters of water when the pump is started, how much water does it hold one hour later?

Question

Water is pumped out of a holding tank at a rate of  3-3e^-0.13t liters/minute, where t is in minutes since the pump is started. If the holding tank contains 1000 liters of water when the pump is started, how much water does it hold one hour later?

anonymous · Answer

integerate 3-3e^-0.31t
then plug 3600 for 1 hour later  
then minus that from 1000

anonymous · Answer

V=1000-3t+3*0.31e^-0.31t
plug  3600 in eauation