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PLZ HELP......you can verify the zeros of the function y=x^2+6x-7 by using a graph and finding where the graph A. is at a minimum B. is at a max C. crosses the x-axis D. crosses the y-axis
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The zeros of a function is where it crosses the x axis
it is c
thank u
:-)
mind helping me again pl
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ok
find the vertex of the parabola by completing the square x^2-6x+8=y
do u need the answer or explanation
◊ Group ◊ y = (x² - 6x) + 8 ◊ Complete the square ◊ y = (x² - 6x + 9) + 8 - 9 ◊ Write as a binomial squared ◊ y = (x-3)² - 1
both plz
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the choose are A.(-3,-6) b(3,-1) C(-3,1) D(-1,3)
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