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OpenStudy (anonymous):
antiderivative(18)/(5-x) = kln[5-x]+c Find the exact value of k that makes the antidifferentiation formula true.
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OpenStudy (anonymous):
got 18 but is wrong
OpenStudy (anonymous):
anti derivative of 18/(5-x) = 18.ln(5-x).(-1) + c
OpenStudy (anonymous):
so k = -18
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