6. Suppose a parabola has vertex (5, –3) and also passes through the point (6, 1). Write the equation of the parabola in vertex form.
(1 point)y = (x – 5)2 – 3
y = 4(x – 5)2 – 3
y = 4(x + 5)2 – 3
y = 4(x – 5)2 + 3

Question

6.   Suppose a parabola has vertex (5, –3) and also passes through the point (6, 1). Write the equation of the parabola in vertex form.
 (1 point)y = (x – 5)2 – 3
y = 4(x – 5)2 – 3
y = 4(x + 5)2 – 3
y = 4(x – 5)2 + 3

anonymous · Answer

you know it looks like 
$$y=a(x-5)^2-3$$ but you do not know $a$ yet
to find it, replace $x$ by $6$, $y$ by $1$ and solve for $a$ 
you get 
$$1=a(6-5)^2-3$$
$$1=a-3$$
$$a=4$$

anonymous · Answer

So, what does it mean when a=4?

anonymous · Answer

@satellite73

anonymous · Answer

OHH i get it thanks :)