Question

Can someone help me?

Replace (...) by x> or equal or x< or equal so that the inequality will be true for any x:
a) x^2-16x+64...0

b) 64+16x+x^2...0

c) -x^2-4x-4...0

d) -x^2+18x-81

Answer 1

I would like to help but I am confused by what you mean in this problem

Answer 2

x^2-16x+64x>=0 ???
x^2-16x+64x<=0 ???

These are your choices?

Answer 3

yea

Answer 4

x^2 - 16x + 64 = (x - 8)^2 ≥ 0
64 + 16x + x^2 = (x - 8)^2 ≥ 0
- x^2 - 4x - 4 = - (x^2 + 4x + 4) = - (x + 2)^2 ≤ 0
- x^2 + 18x - 81 = - (x^2 - 18x + 81) = - (x-9)^2 ≤ 0