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Solve tan x + 1 = 0 for x.
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start with \[\tan(x)=-1\] and then think of points on the unit circle where sine and cosine are the same number except of opposite sign
btw i sent a link with the numerical answer to your last question
tan x + 1 = 0 arc tan (0) = 0 so x+1 = 0 x = -1
??
tan a = b arc tan b = a So a = x +1 b = 0 tan x + 1 = 0 arc tan (0) = 0 x+1 = 0 x = -1
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give a general formual for tan x= -1
tan x = -1 x = arctan (-1) = πn-(π/4), n is integer
x = −π/4 +2nπ
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