If two resistors with resistances R1 and R2 are connected in parallel, as in the figure below, then the total resistance R, measured in ohms (Ω), is given by

1/R = 1/R1 + 1/R2

If R1 and R2 are increasing at rates of 0.3 Ω/s and 0.2 Ω/s, respectively, how fast is R changing when R1 = 80 Ω and R2 = 100 Ω?

Question

If two resistors with resistances R1 and R2 are connected in parallel, as in the figure below, then the total resistance R, measured in ohms (Ω), is given by
 
1/R = 1/R1 + 1/R2

If R1 and R2 are increasing at rates of 0.3 Ω/s and 0.2 Ω/s, respectively, how fast is R changing when R1 = 80 Ω and R2 = 100 Ω?

anonymous · Answer

It's going to be the same method as previously show, please try it, yourself.

anonymous · Answer

*shown

anonymous · Answer

@echo94 Utilizing @LolWolf 's solution as your guideline and feel free to ask :)