Question

factor the expression completely... 6x^3+48

Answer 1

6x^3+48
First take 6 common

Answer 2

can u?

Answer 3

@mathgirl501 ???

Answer 4

i don understand wht you are sking me @sauravshakya

Answer 5

Can you take out a common number with 6 and 48?

Answer 6

6x^3+48
= 6(x^3 + 8)
= 6(x^3 + 2^3)
= 6{(x + 2)[x^2 - (x)(2) + 2^2]}
= 6(x + 2) (x^2 - 2x + 4)

Answer 7

6x^3+48 = 6(x^3+8) = 6(x^3 +2^3)
Now, USE a^3+b^3 = (a+b) (a^2-ab+b^2)

Answer 8

Can u?