Question

Write an equation of a line in slope intercept form that is perpendicular to y = -4x -2 and passes
through the point (-16, -11).

Answer 1

@03225186213

Answer 2

what is the slope of given line?

Answer 3

can u find?

Answer 4

y=-4x-2?

Answer 5

compare
y=mx+c
m is slope
now what is m?

Answer 6

-4?

Answer 7

the slope is -4?

Answer 8

right
now pependicular line has slope = negative invese
m of perpe =-1/m
what is -1/m?

Answer 9

-1/-4?

Answer 10

=1/4 is slope
points are given
plug in equ
y-y1=m(x-x1)
what will be equ?

Answer 11

4-(-11)=-4(-1-(-16)?

Answer 12

@03225186213

Answer 13

no
y-(-11)=1/4(x-(-16)

Answer 14

y+11=1/4x+4
y=1/4x-7

Answer 15

so how do i write everything out lol

Answer 16

you trid but dont put y and x in equ x1 and y1 are given

Answer 17

ok

Answer 18

slope of given line =-4
slope of perpendicular line =-1/m=1/4
equ of perpen having slope 1/4 and passing through (-16, -11). is
y-(-11)=1/4(x-(-16)
y+11=1/4x+4
y=1/4x-7