Question

help
0. Write an equation of a line in slope intercept form that is perpendicular to the line 2x -3y = 12 and
passes through the point (2, 6).

Answer 1

@03225186213

Answer 2

what willl be slope?

Answer 3

2

Answer 4

first take equ in standard form
y=mx+c
now slope?

Answer 5

12?

Answer 6

no
2x-3y=12
-3y=-2x+12
y=2/3x-4
slope ?

Answer 7

3x-4 or 2?

Answer 8

2/3 is coefficient of x so slope =2/3

Answer 9

slope of perpendicular is negative invese of this slope I taught u earlier so slope of per line

Answer 10

ok can u help me with number 1 n 2? imma attatch the file bc it wont let me attactch the pic so here ITS # 1 N 2

Answer 11

slope =y/x
=-2/-5=2/5
equ
y=mx+b b is y intercept b=-2
put m and b in equ
and solve

Answer 12

wait wat does m =?

Answer 13

for 2
eq is
x=3

Answer 14

m slope 2/5

Answer 15

its hard :(

Answer 16

@03225186213

Answer 17

@hartnn can u help me?

Answer 18

ok can u help me with number 1 n 2? imma attatch the file bc it wont let me attactch the pic so here ITS # 1 N 2
7 days ago
1 attachments
writingequations_writingassignment1.pdf

Answer 19

?

Answer 20

@Kira_Yamato can u help me with numbers 1 and 2 in the attached file?

Answer 21

1) y-intercept is -2
Gradient = (0 - (-2)) / (-6-0) = 2/(-6) = -1/3

2) x = 3 (since vertical line intersecting x-axis at 3)