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If a complex number z=x+iy then in terms of conjugate coordinates x can be written as :
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@hartnn
the question is 'x can be.....' or 'z can be....' ?
x can be
then i need options...
z-zbar,z+zbar/2,none of the above
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ohh....so find z bar first, what u get ?
How do i do that is it underroot(x^2+y^2)
ok, if z = a+bi x bar = conjugate = a-bi got this ?
*z bar
Ok
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now what is z bar here ?
zbar=(x-yi)
now to eliminate y here, we add z and z bar what u get ?
z+zbar=(x+yi)+(x-yi)=2x
so whats x ?
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z+zbar/2 .Right Thanks :)
welcome ^_^
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