Question

i need help in C programming ASAP

Answer 1

what's wrong with this picture?

```
void search()
{
int recNum;
char yn[2];

while (1)
{
system("cls");
printf("\n\n\n\n\t\t\t\t SEARCH DATABASE\n");
printf("\t\t\t\t ~~~~~~~~~~~~~~~\n");
recNum = find();
if(recNum == MAXNAMES)
printf("\n\n ENTRY NOT FOUND!!!\n");
printf("\n\n Would you like to search for another entry (Y/N) ? ");
gets(yn);
if( toupper(yn[0]) != 'Y')
break;
}
}

char upstrcmp(char str1[], char str2[])
{
int cntr;

cntr = 0;
while(1)
{
if( toupper(str1[cntr]) != toupper(str2[cntr]) )
return 1;
if( str1[cntr] == '\0' && str2[cntr] == '\0')
return 0;

cntr++;
}
}

int find()
{
int cntr;
char lookName[200];
char yn[2];
char filter[2];

while (1)
{
printf("\n\n\t Search by Filter\n");
printf("\t ~~~~~~~~~~~~~~~~\n");
printf("\n\t F - First Name\n");
printf("\n\t M - Middle Name\n");
printf("\n\t L - Last Name\n");
printf("\n\t S - School\n");
printf("\n\t I - ID Number\n");
printf("\n\t C - College\n");
printf("\n\t D - Degree Program\n");
printf("\n\t A - Address\n");
printf("\n\t T - Telephone Number\n");
printf("\n\t P - Cellphone Number\n");
printf("\n\n\t Enter the letter corresponding to the\n");
printf("\n\t filter you wish to use > ");
gets(filter);
system("cls");
filter[0] = tolower(filter[0]);

if (filter[0] == 'l')
{
printf("\n\n\n Enter last name: ");
gets(lookName);
for (cntr = 0; cntr < MAXNAMES; cntr++)
{
if (lookName[0] == '\0')
return MAXNAMES;
if( !upstrcmp(studDat[cntr].lname, lookName) )
{
printf("\n\n\n Student's Name: %s, %s %s\n", studDat[cntr].lname, studDat[cntr].fname, studDat[cntr].midname);

if (studDat[cntr].school[0] == '\0')
printf("\n School: -----\n");
else
printf("\n School: %s\n", studDat[cntr].school);

if (studDat[cntr].idNum[0] == '\0')
printf("\n ID Number: -----\n");
else
printf("\n ID Number: %s\n", studDat[cntr].idNum);

if (studDat[cntr].colg[0] == '\0')
printf("\n College: -----\n");
else
printf("\n College: %s\n", studDat[cntr].colg);

if (studDat[cntr].degProg[0] == '\0')
printf("\n Degree Program: -----\n");
else
printf("\n Degree Program: %s\n", studDat[cntr].degProg);

if (studDat[cntr].addr[0] == '\0')
printf("\n Address: -----\n");
else
printf("\n Address: %s\n", studDat[cntr].addr);

if (studDat[cntr].celNum[0] == '\0' && studDat[cntr].telNum[0] == '\0')
printf("\n Contact Number: -----\n");
else if (studDat[cntr].telNum[0] == '\0')
printf("\n Contact Number: +63%s\n", studDat[cntr].celNum);
else if (studDat[cntr].celNum[0] == '\0')
printf("\n Contact Number: %s\n", studDat[cntr].telNum);
else
printf("\n Contact Number: %s / +63%s\n", studDat[cntr].telNum, studDat[cntr].celNum);
printf("\n\n Is this the correct entry (Y/N) ? ");
gets(yn);
if( toupper(yn[0]) == 'Y')
break;
}
}
}
else
continue;
}
return(cntr);
}

Answer 2

as the names suggest, its function is for searching a specific entry in a database given a filter

i think my problem is in the find() function

it searches right. But for some reason, the program won't return a "NOT FOUND" if the name is not in the database

Answer 3

the program just returns "NOT FOUND" if the user inputs nothing in the Enter last name part

Answer 4

i have confirmed the for loop is not the problem...so i suppose it would be the return

Answer 5

i have found the problem...it is my search by filter menu...so now the question is...how do i fix it?

Answer 6

i narrowed the problem...it seems it's my while (1) loop

Answer 7

i have found the solution