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Mathematics 16 Online
OpenStudy (baldymcgee6):

L'hospital's rule, stuck...

OpenStudy (baldymcgee6):

http://tinypic.com/r/1z6yrh4/6

OpenStudy (tkhunny):

Rewrite: \[-\frac{-\sin^{2}(x)}{x}\;=\;-\frac{-x\cdot\sin^{2}(x)}{x^{2}}\]

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