Question

calc help! find the extrema on the closed interval. g(x)=2x+5cosx

Answer 1

What interval? c:

Answer 2

g(x)=2x+5cosx
once derived...its... 2-5sinx

Answer 3

o wait ! [0, 2pi]

Answer 4

sorry

Answer 5

\[g'(x)=2-5\sin x\]\[0=2-5\sin x\]\[\sin x=\frac{ 2 }{ 5 }\]\[\arcsin \frac{ 2 }{ 5 }=x\]

So this is how we solve for critical points yes? :o

Answer 6

Which is not a nice special angle :[ grr

Answer 7

idk about the arcsin?????