Question

When the shuttle bus comes to a sudden stop to avoid hitting a dog, it decelerates uniformly at 5.0 m/s 2 as it slows from 9.5 m/s to 0 m/s. Find the time interval of acceleration for the bus. Answer in units of s

Answer 1

a = Δ v/ Δt
-> Δt = Δv/ a
= -9.5 /- 5 = ...

Answer 2

given
acceleration =-5m/s^2
velocity slow down from
v2=9.5 m/s to v1= 0 m/s
if the formula for distance is
s= change in V/ change in t
change in t=change in V/s
t= (0-9.5)/-5
t= ?