Question

sec²x + csc²x =

A) 2secxcscx
B) csc2x
C) 2secx
D) 2csc(2x)
E) sec²x·csc²x

Answer 1

substitute for sec nd csc in terms of sin nd cos

Answer 2

\(\Large \displaystyle \frac{1}{\sin^2 x}+ \frac{1}{\cos^2 x}\) ··· Now what?

Answer 3

take lcm and add them

Answer 4

\[\Huge \frac{\cos^2 x + \sin^2 x}{\sin^2 x \cos^2 x}\]

Answer 5

cos^2x+sin^2x = ?

Answer 6

E.